1. The
giant, single-cell alga Nitella lives
in fresh water and is readily cultured in the laboratory. For this reason and also because of its
large size and favorable optical properties, this alga has been a favorite
object of study by cell biologists and cell physiologists.
Consider the following experiments and answer all
of the following questions concerning the Nitella plasma membrane.
A. (5 pts) Why doesn't this alga swell osmotically and burst in its natural environment? How could you test the validity of your explanation?
B. (5 pts) Using the Fick equation, how would
you determine the permeability coefficient of the Nitella plasma membrane to
water?
C. (5 pts) If you place Nitella in a solution of
10% glycerol and observe it under a phase contrast microscope, you would note
first its shrinkage followed by a gradual return to its normal shape. What is the simplest accurate explanation of
these results?
D.
(8 pts) Like other cells Nitella exhibits a
membrane, or "resting", potential whereby its cytoplasm is negative
with respect to its environment. The
actual value of this potential (at 20o C) is - 138 mV. How is this potential likely generated and
how could you test your hypothesis?
(Your reasoning must be explicit and detailed and all relevant
calculations must be shown.) The
intracellular and extracellular concentrations of the major inorganic ions, as
well as log values for their concentration ratios, are indicated below.
|
|
Concentration in mM |
Logs of Concentration Ratios |
||
|
Location |
Na+ |
K+ |
Cl- |
Nai/Nao
= 1.15 Nao/Nai = -1.15 |
|
cytoplasm |
14.0 |
119.0 |
65.0 |
Ko/Ki
= -3.08 Ki/Ko = 3.08 |
|
stream/culture |
1.0 |
0.1 |
1.3 |
Cli/Clo
= 1.70 Clo/Cli = -1.70 |
The first
three questions may be answered on the following page; the last question
later. Remember! What useful information is provided by the
question, what must you remember from text and reading, and what questions are
(and are not) being asked?
A.
B.
C.
Having
answered the questions yourself, now consider the following answers others
provided.
A. Why
doesn't this alga swell osmotically and burst in its natural environment? How could you test the validity of your
explanation?
|
ANSWER |
COMMENT |
|
Example
1. Most likely, this organism has a
number of "pumps" to take in solutes against their gradients,
keeping the cell from hemolysing.
There are a number of ways to test this hypothesis. One way would be to introduce an inhibitor
that binds to the "pump" sites and restricts pumping of solutes
(e.g., ouabain). |
Interesting answer and logical test, but wrong! Pumping in solute would make osmotic
gradient steeper, causing more water to diffuse inwards by osmosis. |
|
Example
2. Osmosis occurs only on the tail of
another ion which is diffusing, as in binding to a polar molecule or ion (ex.
Na+). If these
concentrations are kept at a certain level in the cell, the water will not be
admitted. To test this, change the
concentration of the water carrier in or out of the cell and monitor the rate
of osmosis. |
Principle is partially correct, but very unlikely that solute
concentration in cytoplasm is equal to solute in fresh water. It is unclear what test is showing. |
|
Example
3. Due to high concentrations of
intercellular ions and other substances the flow of H2O according
to the activity gradient into the cell by osmosis, Nitella must have a system
for regulating H2O flow.
Diffusion is determined by polarity and molecular size. Although H2O is polar and
therefore not readily admissible it is so small it usually passes through the
membrane uninhibited. Nitella may
have developed a membrane which is relatively impermeable to H2O. This solutions would prevent excess H2O
from entering the cell. Another
possible explanation is that Nitella has developed a pump system to remove
excess H2O from its interior.
The probable explanation contains both these elements. One way
to test this hypothesis is through an examination of Nitella's permeability
according to the Fick equation. A
method to test the possibility of a system for removing excess H2O
could be developed by labeling H2O within the cell by means of a
dye and observing to see if this H2O is removed from the cell to
the surrounding medium. |
Good
opening sentience but answer is very wordy. Much of second and third
sentences is irrelevant. Relatively impermeable membrane
would only affect rate of H2O entry, but cell would eventually
swell and burst. There are no known H2O
pumps! Creative, but must first rule
out simpler explanations. Excellent test of weak
(unlikely) hypothesis. |
B. Using
the Fick equation, how would you determine the permeability coefficient of the Nitella
plasma membrane to water?
|
ANSWER |
COMMENTARY |
|
Example
1. Taking the Fick equation, I would
test the rate of diffusion across the Nitella plasma membrane and compare it
to the other substances of known permeability coefficients. By creating a solution where only water
was moved across the membrane the rate of diffusion could be calculated
comparing the rate of diffusion to other substances of known permeability
coefficients the permeability coefficient of Nitella could be obtained. |
Where's the Fick equation? Comparison of the permeability coefficient
of H2O with that of other substances irrelevant here. How is
the rate of diffusion to measured? Weak answer! |
|
Example
2. To determine the permeability, you
would want to hemolyze cells. It
would be calculated by dividing the change in the H2O
concentration by the time it took.
Then plug in for [H2Oo] and [H2Oi]--this
will give you K. It's really a pointless
calculation because everything happens so fast that the permeability
coefficient is huge and meaningless. |
Where's the Fick equation? Nitella won't
"hemolyze"--see answer to Question A. How is the concentration of H2O
measured? What does it mean to talk
about the concentration of a solvent? Dont fight the question! The student here doesnt know enough to
draw this conclusion. |
|
Example
3. We can measure in laboratory the
rate of diffusion of particles and we also can control the solute
concentrations inside and outside of the cell. Therefore we can determine the coefficient of permeability. |
Good start at an answer! Variables need to be related, with
constants, to rate. State the Fick equation! |
All three answers suffer from the same
weakness. If the questions requires the
use of an equation to dermine a solution, the equation must be used.
C. If you place Nitella in a solution of 10%
glycerol and observe it under a phase contrast microscope, you would note
first, an immediate shrinkage (of both the cell and its central vacuole) and
then a gradual return to its normal shape.
What is the simplest, accurate explanation of these results?
|
ANSWER |
COMMENTARY |
|
Example
1. Nitella, in its natural environment
exists in a situation in which the outside environment contains much less
solute than its interior. Therefore
if it is immediately immersed in a 10% glycerol solution, it will atrophy due
to loss of H2O moving out of the cell according to the activity gradient--the
higher concentration of solute outside this cell. Gradually the cell would
adjust to the situation by regulation of its H2O uptake and loss
and regain the concentration of solute/H2O which is necessary for
its survival. This ability to regulate
the flow of H2O allows Nitella to exist in solutions of various
concentrations. |
Good answer so far! although atrophy is the wrong verb. Vague--how does water regulation
work and how would it affect outcome? Last sentence interesting but
irrelevant. |
|
Example
2. Phase contrast gives good contrast
observation so that substances are dark enough to see instead of the
faintness you might get under bright field.
However, what is lost is the little details (physically) that you
would have been able to note under bright field. That may account for the shrinkage at first of the cell and
vacuole. Perhaps it was losing detail
in favor of a sharper, more focused albeit smaller image. The other explanation is that glycerol is
an alcohol with a polar -OH end (from the electronegative oxygen). It is more difficult for polar molecules
to pass through membranes so their rate of passage is considerably slower. So perhaps this "gradual return"
could be attributed to the time it may take for the glycerol to move into Nitella. |
First part of answer suggests
initial change is an optical artefact.
Accept the details provided at face value: Dont side-step the question. Second part of answer changes
tack and is essentially correct, but doesn't address initial shrinking (due
to H2O loss) in an explicit manner. (Focus changes, resulting in an
incomplete answer!) |
|
Example
3. This would suggest that the
glycerol is some what hyperosmotic solution which causes the slight
crenation, however, the restoration of the cell's shape and the fact that
this is at room temperature indicate that a dynamic equilibrium has been
restored. |
How does crenation result from a
hyperosmotic environment? What is a
"dynamic equilibrium"?
Answer is much too general. It
may reflect complete understanding, but
answer lacks sufficient detail. |
D. Like other cells Nitella exhibits a membrane,
or "resting", potential whereby its cytoplasm is negative with
respect to its environment. The actual
value of this potential (at 18o C) is - 138 mV. How is this potential likely to be generated
and how could you test your hypothesis?
(Your reasoning must be explicit and detailed and all relevant
calculations must be shown.) The
intracellular and extracellular concentrations of the major inorganic ions, as
well as log values for their concentration ratios, are indicated below.
|
|
Concentration in mM |
Logs of Concentration Ratios |
||
|
Location |
Na+ |
K+ |
Cl- |
Nai/Nao
= 1.15 Nao/Nai = -1.15 |
|
cytoplasm |
14.0 |
119.0 |
65.0 |
Ko/Ki
= -3.08 Ki/Ko = 3.08 |
|
stream/culture |
1.0 |
0.1 |
1.3 |
Cli/Clo
= 1.70 Clo/Cli = -1.70 |
Answer the question below
and then continue on to examine other answers.
|
ANSWERS |
COMMENTARY |
|
Example
1. This resting potential is
generated because ions are moving in and out of the cell. It is negative because ions like Na+ and
K+ are leaving the making the cytoplasm negative The log of Na outside/Na inside is negative so that is why the
resting potential is negative. The
hypothesis could be tested by changing the concentrations outside and inside
and determining the change difference in the membrane potential. |
Generally true answer, but
lacking calculations, it's much too vague. Test is correct, but what exactly would results show? |
|
Example
2. The resting potential is
determined by the electro chemical gradient that is maintained by the
cell. It takes into account the
changed ions of Na+, K+, Cl-. The
electro chemical gradient is determined by the Nerst equation. v = . In determining the resting potential the permeability of each
ion must also be considered and factored into the equation. To test the hypothesis to see if
it is these ions that make up the resting potential, one could place the cell
in a test solution that is higher in concentration of the ions than the
cell. A voltage meter may be inserted
into the cell and the solution, to see if the resting potential is changed. |
Accurate answer but no
calculations shown; therefore, answer is incomplete. Good test, but . . . . . . how specifically would
voltage change under condition described? |